Decimal.Round() Method in C# | Set - 1

Decimal.Round Method is used to round a value to the nearest integer or a specified number of decimal places. There are 4 methods in the overload list of this method as follows:

Round(Decimal) Method

Round(Decimal, Int32) Method

Round(Decimal, MidpointRounding) Method

Round(Decimal, Int32, MidpointRounding) Method

Here, we will discuss the first two methods.

Decimal.Round(Decimal) Method

This method is used to round a decimal value to the nearest integer.

Syntax: public static decimal Round (decimal d); Here, it takes a decimal number to round. Return Value: This method returns the integer which is nearest to the d parameter. If d is halfway between two integers, one of which is even and the other odd, the even number is returned. Exceptions: This method throws OverflowException if the result is outside the range of a Decimal value.

Below programs illustrate the use of Decimal.Round(Decimal) Method: Example 1:

csharp

// C# program to demonstrate the
// Decimal.Round(Decimal) Method
using System;

class GFG {

    // Main Method
    public static void Main()
    {
        try {

            // Declaring and initializing value
            decimal value = 184467440737095.51615M;

            // getting rounded decimal
            // using Round() method
            decimal round = Decimal.Round(value);

            // Display the value
            Console.WriteLine("Rounded value is {0}", round);
        }

        catch (OverflowException e) 
        {
            Console.WriteLine("Value must not be out of bound");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

Output:

Rounded value is 184467440737096

Example 2: For OverflowException

csharp

// C# program to demonstrate the
// Decimal.Round(Decimal) Method
using System;

class GFG {

    // Main Method
    public static void Main()
    {

        try 
        {

            // Declaring and initializing value
            decimal value = 79228162514264337593543950335.5M;

            // getting rounded decimal
            // using Round() method
            decimal round = Decimal.Round(value);

            // Display the value
            Console.WriteLine("Rounded value is {0}", round);
        }

        catch (OverflowException e) 
        {
            Console.WriteLine("Value must not be out of bound");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

Compile-Time Errors:

prog.cs(15,51): error CS0594: Floating-point constant is outside the range of type `decimal'

Round(Decimal, Int32) Method

This method is used to round a Decimal value to a specified number of decimal places.

Syntax: public static decimal Round (decimal d, int decimals); Parameters: d: It is a decimal number which is to be rounded. decimals: It is a value from 0 to 28 that specifies the number of decimal places to round to.

Return Value: This method returns the decimal number equivalent to d rounded to decimals number of decimal places. Exception: This method throws ArgumentOutOfRangeException if decimals is not a value from 0 to 28. Below programs illustrate the use of Decimal.Round(Decimal, Int32) Method: Example 1:

csharp

// C# program to demonstrate the
// Decimal.Round(Decimal) Method
using System;

class GFG {

    // Main Method
    public static void Main()
    {
        try {

            // Declaring and initializing value
            decimal value = 7922816251426433759354.39503305M;

            // getting rounded decimal
            // using Round() method
            decimal round = Decimal.Round(value, 4);

            // Display the value
            Console.WriteLine("Rounded value is {0}", round);
        }

        catch (ArgumentOutOfRangeException e) 
        {
            Console.WriteLine("decimal place is not within bound");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

Output:

Rounded value is 7922816251426433759354.3950

Example 2: For ArgumentOutOfRangeException

csharp

// C# program to demonstrate the
// Decimal.Round(Decimal) Method
using System;

class GFG {

    // Main Method
    public static void Main()
    {
        try 
        {

            // Declaring and initializing value
            decimal value = 7922816251426433759354.39503305M;

            // getting rounded decimal
            // using Round() method
            decimal round = Decimal.Round(value, 29);

            // Display the value
            Console.WriteLine("Rounded value is {0}", round);
        }

        catch (ArgumentOutOfRangeException e) 
        {
            Console.WriteLine("Decimal place is not within bound");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

Output:

Decimal place is not within bound
Exception Thrown: System.ArgumentOutOfRangeException

Reference:

https://learn.microsoft.com/en-us/dotnet/api/system.decimal.round?view=netframework-4.7.2

Decimal.Round() Method in C# | Set - 1

Decimal.Round(Decimal) Method

Round(Decimal, Int32) Method

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