Print * in place of characters for reading passwords in C

While writing a C program, if you want to type password and it should not be visible on screen or an * symbol is to be printed. Examples:

Input : abcdefg
Output : *******

Note : Below solution uses getch() which may not work on all compilers as this is a non-standard function.

// C program to print * 
// in place of characters
#include<stdio.h>
#include<conio.h>
int main(void){
    char password[55];

    printf("password:\n");
    int p=0;
    do{
        password[p]=getch();
        if(password[p]!='\r'){
            printf("*");
        }
        p++;
    }while(password[p-1]!='\r');
    password[p-1]='&#092;&#048;';
    printf("\nYou have entered %s as password.",password);
    getch();
}

Time Complexity: O(n)

Here n is the length of the password

Auxiliary Space: O(n)

The extra space is used to store the password.

Explanation: Basically it is taking the characters we enter through getch() function and print * instead of it for every letter we type. Remark: It doesn't run in this IDE, download this file and run in your terminal.

Print * in place of characters for reading passwords in C

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