How to wake up a std::thread while it is sleeping?

In this article, we will discuss how to wake up a std::thread while it is sleeping. It is known that a thread can't be exited when it is sleeping. So it is woken up using a command as:

std::condition_variable

Below is the pseudo-code to implement the same:

C++

// Custom Class
struct MyClass {

    // Constructor
    MyClass()
        : my_thread([this]() {
            this->thread();
        })
    {
    }

    // Destructor
    ~MyClass()
    {
        {
            std::lock_guard<std::mutex> l(m_);
            stop_ = true;
        }
        c_.notify_one();
        my_thread.join();
    }

    // Function that implements the
    // thread
    void thread()
    {
        while (this->wait_for(std::chrono::minutes(2)))
            SendStatusInfo(some_info);
    }

    // Function to returns false when
    // the thread is stopped
    template <class Duration>
    bool wait_for(Duration duration)
    {
        std::unique_lock<std::mutex> l(m_);
        return !c_.wait_for(l, duration, [this]() {
            return stop_;
        });
    }

    // Conditions Variable
    std::condition_variable c_;
    std::mutex m_;
    bool stop_ = false;
    std::thread my_thread;
};

Below is another example to illustrate the same:

std::promise/std::future

The above command can be used as a simpler alternative to the former method. In this case, a Future is not susceptible to false wakes and doesn't require a mutex for synchronization. Below is the pseudo-code to implement the same:

C++

// Promise Condition
std::promise<void> pr;

// Start the thread
std::thread thr{
        [fut = pr.get_future()]{

            // Iterate until the condition
            // break
            while (true){
                if (fut.wait_for(std::chrono::minutes(2))
                    != std::future_status::timeout) return;
}
}
}
;

// When ready to stop
pr.set_value();

// Join the thread
thr.join();

Below is the program to illustrate the above concepts:

C++

// C++ program to illustrate the waking
// of the thread while it is sleeping
#include <bits/stdc++.h>
using namespace std;

std::deque<int> q;
std::mutex mu;
std::condition_variable cond;

// Function to create the thread 1
void function_1()
{
    // Initialize a counter variable
    int count = 10;

    // Iterate until count is positive
    while (count > 0) {

        // Mutex
        std::unique_lock<mutex> locker(mu);

        // Push the current count in
        // the dequeue
        q.push_front(count);
        locker.unlock();
        cond.notify_one();

        // If there is any waiting thread
        // then notify that thread
        std::this_thread::sleep_for(
            chrono::seconds(1));

        // Decrement the count
        count--;
    }
}

// Function to create the thread 2
void function_2()
{
    // Initialize a variable to get
    // the data from the deque
    int data = 0;

    while (data != 1) {

        std::unique_lock<mutex> locker(mu);

        cond.wait(locker, []() {
            return !q.empty();
        });

        // False Waking of thread
        data = q.back();
        q.pop_back();
        locker.unlock();

        // Print the message
        cout << "t2 got a value from"
                " t1"
             << data << '\n';
    }
}

// Driver Code
int main()
{
    // Create thread 1
    std::thread t1(function_1);

    // Create thread 2
    std::thread t2(function_2);

    // Join the threads
    t1.join();
    t2.join();

    return 0;
}

Output:

How to wake up a std::thread while it is sleeping?

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