Given a positive number n (n > 1), round-off this number to a given no. of significant digits, d.
Examples:
Input : n = 139.59
d = 4
Output : The number after rounding-off is 139.6 .
The number 139.59 has 5 significant figures and for rounding-off
the number to 4 significant figures, 139.59 is converted to 139.6 .
Input : n = 1240
d = 2
Output : The number after rounding-off is 1200 .
What are significant figures?
Each of the digits of a number that are used to express it to the required degree of accuracy, starting from the first non-zero digit, are called as significant figures.
Since there are numbers with large number of digits, for example,
Significant digits include all the digits in a number falling in one of the following categories -
- All non-zero digits.
- Zero digits which-
- lie between significant digits.
- lie to the right of decimal point and at the same time to the right of a non-zero digit.
- are specifically indicated to be significant.
The following table shows numbers and no. of significant digits present in them -

Rules for Rounding-off a Number
To round off a number to n significant figures-
- Discard all digits to the right of nth significant digit.
- If this discarded number is-
- less than half a unit in nthplace, leave the nth digit unchanged.
- greater than half a unit in the nth place, increase the nth digit by unity.
- exactly half a unit in the nth place, increase the nth digit by unity if its odd, otherwise leave it unchanged.
The following table shows rounding-off a number to a given no. of significant digits -

// C++ program to round-off a number to given no. of
// significant digits
#include <bits/stdc++.h>
using namespace std;
// Function to round - off the number
void Round_off(double N, double n)
{
int h;
double l, a, b, c, d, e, i, j, m, f, g;
b = N;
c = floor(N);
// Counting the no. of digits to the left of decimal point
// in the given no.
for (i = 0; b >= 1; ++i)
b = b / 10;
d = n - i;
b = N;
b = b * pow(10, d);
e = b + 0.5;
if ((float)e == (float)ceil(b)) {
f = (ceil(b));
h = f - 2;
if (h % 2 != 0) {
e = e - 1;
}
}
j = floor(e);
m = pow(10, d);
j = j / m;
cout << "The number after rounding-off is " << j;
}
// Driver main function
int main()
{
double N, n;
// Number to be rounded - off
N = 139.59;
// No. of Significant digits required in the no.
n = 4;
Round_off(N, n);
return 0;
}
// Java program to round-off a number to given no. of
// significant digits
import java.io.*;
import static java.lang.Math.*;
public class A {
// Function to round - off the number
static void Round_off(double N, double n)
{
int h;
double l, a, b, c, d, e, i, j, m, f, g;
b = N;
c = floor(N);
// Counting the no. of digits to the left of decimal point
// in the given no.
for (i = 0; b >= 1; ++i)
b = b / 10;
d = n - i;
b = N;
b = b * pow(10, d);
e = b + 0.5;
if ((float)e == (float)ceil(b)) {
f = (ceil(b));
h = (int)(f - 2);
if (h % 2 != 0) {
e = e - 1;
}
}
j = floor(e);
m = pow(10, d);
j = j / m;
System.out.println("The number after rounding-off is "
+ j);
}
// Driver main function
public static void main(String args[])
{
double N, n;
// Number to be rounded - off
N = 139.59;
// No. of Significant digits required in the no.
n = 4;
Round_off(N, n);
}
}
# Python 3 program to round-off a number
# to given no. of significant digits
from math import ceil, floor, pow
# Function to round - off the number
def Round_off(N, n):
b = N
c = floor(N)
# Counting the no. of digits
# to the left of decimal point
# in the given no.
i = 0;
while(b >= 1):
b = b / 10
i = i + 1
d = n - i
b = N
b = b * pow(10, d)
e = b + 0.5
if (float(e) == float(ceil(b))):
f = (ceil(b))
h = f - 2
if (h % 2 != 0):
e = e - 1
j = floor(e)
m = pow(10, d)
j = j / m
print("The number after rounding-off is", j)
# Driver Code
if __name__ == '__main__':
# Number to be rounded - off
N = 139.59
# No. of Significant digits
# required in the no.
n = 4
Round_off(N, n)
# This code is contributed by
# Surendra_Gangwar
// C# program to round-off a number
// to given no. of significant digits
using System;
class A {
// Function to round - off the number
static void Round_off(double N, double n)
{
int h;
double b, d, e, i, j, m, f;
b = N;
// c = Math.Floor(N);
// Counting the no. of digits to the
// left of decimal point in the given no.
for (i = 0; b >= 1; ++i)
b = b / 10;
d = n - i;
b = N;
b = b * Math.Pow(10, d);
e = b + 0.5;
if ((float)e == (float)Math.Ceiling(b)) {
f = (Math.Ceiling(b));
h = (int)(f - 2);
if (h % 2 != 0) {
e = e - 1;
}
}
j = Math.Floor(e);
m = Math.Pow(10, d);
j = j / m;
Console.WriteLine("The number after " +
"rounding-off is " + j);
}
// Driver main function
public static void Main()
{
double N, n;
// Number to be rounded - off
N = 139.59;
// No. of Significant digits required in the no.
n = 4;
Round_off(N, n);
}
}
// This code is contributed by vt_m.
<?php
// PHP program to round-off
// a number to given no. of
// significant digits
// Function to round -
// off the number
function Round_off($N, $n)
{
$h;
$l; $a; $b; $c;
$d; $e; $i; $j;
$m; $f; $g;
$b = $N;
$c = floor($N);
// Counting the no. of digits
// to the left of decimal point
// in the given no.
for ($i = 0; $b >= 1; ++$i)
$b = $b / 10;
$d = $n - $i;
$b = $N;
$b = $b * pow(10, $d);
$e = $b + 0.5;
if ($e == ceil($b))
{
$f = (ceil($b));
$h = $f - 2;
if ($h % 2 != 0)
{
$e = $e - 1;
}
}
$j = floor($e);
$m = pow(10, $d);
$j = $j / $m;
echo "The number after rounding-off is " ,$j;
}
// Driver Code
$N; $n;
// Number to be rounded - off
$N = 139.59;
// No. of Significant digits
// required in the no.
$n = 4;
Round_off($N, $n);
// This code is contributed by anuj_67
?>
<script>
// Javascript program to round-off a number to given no. of
// significant digitsimport
// Function to round - off the number
function Round_off(N , n)
{
var h;
var l, a, b, c, d, e, i, j, m, f, g;
b = N;
c = Math.floor(N);
// Counting the no. of digits to the left of decimal point
// in the given no.
for (i = 0; b >= 1; ++i)
b = parseInt(b / 10);
d = n - i;
b = N;
b = b * Math.pow(10, d);
e = b + 0.5;
if (e == Math.ceil(b)) {
f = (Math.ceil(b));
h = parseInt(f - 2);
if (h % 2 != 0) {
e = e - 1;
}
}
j = Math.floor(e);
m = Math.pow(10, d);
j = j / m;
document.write("The number after rounding-off is "
+ j);
}
// Driver main function
var N, n;
// Number to be rounded - off
N = 139.59;
// No. of Significant digits required in the no.
n = 4;
Round_off(N, n);
// This code contributed by Princi Singh
</script>
Output:
The number after rounding-off is 139.6
Time complexity: O(logN)
Space complexity: O(1)