Limits in mathematics are defined as the values that a function approaches for given input values. Limits play a vital role in calculus and mathematical analysis and are used to define derivatives, integrals, and continuity.
Limits are unique real numbers. Let us consider a real-valued function “f” and the real number “p”, the limit is normally written as
Limx→p f(x) = L
It is read as “the limit of f of x, as x approaches p equals L”. The “lim” shows the limit and the fact that the function f(x) approaches the limit L as the right arrow describes x approaches p.
Limits Important Formulas
limx→0 (sin x) = 0
limx→0 (cos x) = 1
limx→0 (
\frac {sinx} {x} )= 1limx→0
\frac {ln(1+x)} {x} = 1limx→0 log ex = 0
limx→e log x = 1
limx→0
\frac {e^x - 1} {x} = 1limx→0
\frac {a^x - 1} {x} = ln a
Limits: Practice Questions with Solution
Problem 1: Find the value of limx→0 x2 + 1
Solution:
We have,
limx→0 x2 + 1
Put x= 0 directly, we get value of limit as 1.
Problem 2: Check for the limit,
Solution:
\lim_{{x \to 0}} \frac{\sin x}{x} = 1
Problem 3: Evaluate lim x→3 (
Solution:
Given
\frac{x^2 - 9}{x - 3} =\frac {(x - 3) (x + 3)} {x - 3)} = x+3
lim x→3 (x + 3) = 3 + 3 = 6.
Problem 4: Evaluate lim x→∞
Solution:
Divide the numerator and the denominator by x3
lim x→∞
\frac{5 - \frac{2}{x^2} + \frac{7}{x^3}}{1 + \frac{4}{x} + \frac{3}{x^3}} = 5 − 0 + 0 / 1 + 0 + 0
= 5
Problem 5: Evaluate lim x→0 tanx.
Solution:
limx → 0 tan(x) = 0
Problem 6: Evaluate limx→2 (8 - 3x + 12x2).
Solution:
limx→2 (8 - 3x + 12x2)
= 8 - (3 x 2) + (12 x 4)
= 50
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Limits Practice Problems: Unsolved
Problem 1: Evaluate limx→2 (3x - 5).
Problem 2: Evaluate lim x→0
Problem 3: Evaluate lim x→1
Problem 4: Evaluate lim x→∞
Problem 5: Evaluate lim x→0 ex - 1.
Problem 6: Evaluate lim x→3
Problem 7: Evaluate lim x→2
Problem 8: Evaluate lim x→3 x - 3.
Problem 9: Evaluate lim x→0 ex.
Problem 10: Evaluate lim x→3 x - 1.