Statistics Practice Questions - Basic

Last Updated : 18 Jun, 2026

Statistics is the branch of mathematics that deals with collecting, organizing, analyzing, interpreting, and presenting data.

  • It helps us make sense of complex data and draw meaningful conclusions for decision-making or predictions.

Question 1: If the marks scored by the students in a class test out of 50 are,

Marks0-1010-2020-3030-4040-50
Number of Students58963

a) What is the class interval of 20 - 30 ?
b) How many students scored in the range of 20 - 40?

Solution:

a) Class interval = Upper limit - Lower limit
Class interval of 20-30 = 30 - 20 = 10

b) The number of students scored in range of 20 - 40 = frequency of class 20 - 30 + frequency of class 30 - 40
The number of students scored in range of 20 - 40 = 9 + 6 = 15

Question 2: Calculate the average of the following numbers: 6, 8, 2, 3, 12, 14.
Solution:

Mean = Sum of all given observations/ Total number of observations

Total number of observations = 6
Mean = 6 + 8 + 2 + 3 + 12 + 14 / 6 = 45/6 = 7.5

Thus, the Mean of 6, 8, 2, 3, 12, 14 is 7.5

Question 3: Find the mean of the first 10 even numbers.
Solution:

Sum of first n even numbers = n × (n + 1)

Sum of first 10 even numbers = 10 × ( 10 + 1) = 10 × 11 = 110
Mean of first 10 even numbers = 110 / 10 = 11

Thus, the mean of first 10 even numbers is 11.

Questions 4: The following are the monthly salaries (in $1000s) of 15 employees in a company:
30, 45, 25, 35, 40, 50, 60, 55, 45, 50, 25, 35, 40, 45, 50.
Find the median salary.

Solution:

Sort the data: [25, 25, 30, 35, 35, 40, 40, 45, 45, 45, 50, 50, 50, 55, 60].

Total number of elements (N) = 15 (odd).
Median = \frac{N}{2}^{th}\ term = 45.

Question 5: The following table represents the marks obtained by students in a test. Find the median of the marks.

Class IntervalFrequency
0–205
20–408
40–6012
60–8015
80–10010

Solution:

Calculate the cumulative frequency:

Class IntervalFrequencyCumulative Frequency
0–2055
20–40813
40–601225
60–801540
80–1001050

Total frequency (N) = 50.

Median class = class where \frac{N}{2}^{th}observation \frac{50}{2} = 25 exists.
Median class = 40 – 60.

Median = L + \left( \frac{\frac{N}{2} - F}{f} \right) \cdot h

Where:
L = 40 (lower boundary of the median class),
N=50 ( total number of observations )
F = 13 ( cumulative frequency before the median class ),
f = 12 (frequency of the median class),
h=20 (class width).

Substituting the values:
Median = 40 + \left( \frac{25 - 13}{12} \right) \cdot 20
Median = 40 + \left( \frac{12}{12} \right) \cdot 20 = 40 + 20 = 60

Question 6: The following table shows the marks scored by students in a test. Calculate the mean using the assumed mean method.

Class IntervalFrequency
10–205
20–308
30–4012
40–5015
50–6010

Solution:

Choose A=35 (assumed mean).
Calculate di = xi − A , where xi​ is the class midpoint.

Class IntervalFrequency (fi​)Midpoint (xi​)di=xi − Afi⋅di
10–20515−20−100
20–30825−10−80
30–40123500
40–50154510150
50–60105520200
  • ∑fi​ = 50
  • ∑fidi = 170

For assumed mean method :

Mean ( \bar x) = A + \frac{\sum f_i \ d_i}{\sum f_i}

Mean = 35 + \frac{170}{50} = 35 + 3.4 = 38.4

Question 7: The following table shows the daily wages of workers in a factory. Use the assumed mean method to calculate the mean daily wage.

Wages (in ₹)Frequency
50–606
60–7010
70–8020
80–9012
90–1008

Solution:

Assume A = 75 (from the midpoint of the central class, 70–80).

Find the midpoints (xi):

Class IntervalFrequency (fi)Midpoint (xi​)di=xi−Afi⋅di
50–60655−20-20−20−120-120−120
60–701065−10-10−10−100-100−100
70–802075000000
80–901285101010120120120
90–100895202020160160160

Apply the formula for the mean:

Mean = A + \frac{\sum f_i d_i}{\sum f_i}

Substitute the values:

  • ∑fi = 56
  • ∑fidi=60

Mean = 75 + \frac{60}{56}​ = 75 + 1.07 = 76.07

Question 8: Find the mode of the following dataset representing the number of hours studied by students in a week:
6, 8, 9, 6, 7, 8, 6, 9, 7, 8, 8, 6, 7, 8, 9

Solution:

Organize the data and count the frequency of each value:

Hours StudiedFrequency
64
73
85
93

Identify the mode:
The mode is the value with the highest frequency.
Mode = 8 (Frequency: 5)

Question 9: Find the mode for the following frequency distribution of students' marks:

Marks IntervalFrequency
10–203
20–307
30–4012
40–5018
50–6010
60–705

Solution:

Identify the modal class: The class with the highest frequency is 40–5040–5040–50, so it is the modal class.

Mode = L + \left( \frac{f_m - f_1}{2f_m - f_1 - f_2} \right) \cdot h

Where:

  • L = 40 (lower boundary of the modal class),
  • fm = 18 (frequency of the modal class),
  • f1 = 12 (frequency of the class before modal class),
  • f2 = 10 (frequency of the class after modal class),
  • h=10 (class width).

Mode = 40 + \left( \frac{18 - 12}{2(18) - 12 - 10} \right) \cdot 10

Mode = 40 + \left( \frac{6}{36 - 22} \right) \cdot 10

Mode = 40 + \left( \frac{6}{14} \right) \cdot 10

Mode = 40 + 4.29 = 44.29

Question 10: A dataset is positively skewed. If the mode is 40 and the median is 45, find the mean using the relationship between mean, median, and mode.

Solution:

Using the formula: Mode = 3(Median) − 2(Mean)

Mode = 3(45)−2(40)= 135 − 80 = 55

Practice Questions

Question 1: The following table represents the heights (in cm) of a group of students:

Height (cm)Frequency
140–1505
150–16012
160–1708
170–18010

Find the class width of the intervals.

Question 2: Given the following raw data:
35, 40, 42, 45, 50, 52, 55, 60, 65, 68, 70, 72
Find the frequency of the values ranging from 40 to 60.

Question 3: The following data represents the marks scored by students in a test:

Marks IntervalFrequency
10–205
20–307
30–408
40–5010
50–605

Calculate the mean using the direct method.

Question 4: The wages of workers in a factory are shown below. Use the assumed mean method to calculate the mean wage:

Wages ( ₹)Frequency
200–3006
300–4008
400–50015
500–60010
600–7005

Question 5: The following data represents the monthly expenses (in $) of 12 families: 450, 500, 550, 600, 620, 700, 720, 750, 800, 850, 900, 950. Find the median of the dataset.

Question 6: The table below shows the marks obtained by students in a class:

Marks IntervalFrequency
10–204
20–308
30–4010
40–5015
50–6012

Find the mode using the formula for grouped data.

Question 7: The following table represents the number of hours students spent studying:

Hours StudiedFrequency
0–24
2–46
4–610
6–88
8–105

Find the median using the formula for grouped data.

Question 8: The following dataset represents the number of books borrowed by students in a week: 2, 3, 5, 3, 4, 3, 2, 5, 3, 2, 4, 5, 3, 3, 4. Find the mode of the dataset.

Question 9: The mean and median of a dataset are given as 25 and 22, respectively. Use the relationship between mean, median, and mode to calculate the mode.

Question 10: Given the frequency distribution below, answer the following questions:

  • a) What is the total frequency?
  • b) Identify the modal class.
  • c) Calculate the median class.
Class IntervalFrequency
0–106
10–2012
20–3018
30–4014
40–5010

Answer key

  1. 10
  2. 7
  3. 35.86
  4. 450
  5. 710
  6. 46.25
  7. 5.3
  8. 3
  9. 16
  10. a) 60
    b) 20-30
    c) 30-40
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