Given dictionary list, extract dictionary with maximum keys.
Input : test_list = [{"gfg": 2, "best" : 4}, {"gfg": 2, "is" : 3, "best" : 4, "CS" : 9}, {"gfg": 2}] Output : 4 Explanation : 2nd dictionary has maximum keys, 4. Input : test_list = [{"gfg": 2, "best" : 4}, {"gfg": 2}] Output : 2 Explanation : 1st dictionary has maximum keys, 2.
Method #1 : Using len() + loop
In this, we iterate for each of dictionary and compare lengths of each, record and return one with maximum length.
# Python3 code to demonstrate working of
# Dictionary with maximum keys
# Using loop + len()
# initializing list
test_list = [{"gfg": 2, "best" : 4},
{"gfg": 2, "is" : 3, "best" : 4},
{"gfg": 2}]
# printing original list
print("The original list is : " + str(test_list))
res = {}
max_len = 0
for ele in test_list:
# checking for lengths
if len(ele) > max_len:
res = ele
max_len = len(ele)
# printing results
print("Maximum keys Dictionary : " + str(res))
Output
The original list is : [{'gfg': 2, 'best': 4}, {'gfg': 2, 'is': 3, 'best': 4}, {'gfg': 2}]
Maximum keys Dictionary : {'gfg': 2, 'is': 3, 'best': 4}
Method #2 : Using max() + key=len
In this, we compute maximum length key using max() by passing additional key "len" for comparison based on lengths.
# Python3 code to demonstrate working of
# Dictionary with maximum keys
# Using max() + key = len
# initializing list
test_list = [{"gfg": 2, "best" : 4},
{"gfg": 2, "is" : 3, "best" : 4},
{"gfg": 2}]
# printing original list
print("The original list is : " + str(test_list))
# maximum length dict using len param
res = max(test_list, key = len)
# printing results
print("Maximum keys Dictionary : " + str(res))
Output
The original list is : [{'gfg': 2, 'best': 4}, {'gfg': 2, 'is': 3, 'best': 4}, {'gfg': 2}]
Maximum keys Dictionary : {'gfg': 2, 'is': 3, 'best': 4}
