What’s going to happen when we compile and run the following C program snippet? C #include "stdio.h" int main() { int a = 10; int b = 15; printf("=%d",(a+1),(b=a+2)); printf(" %d=",b); return 0; }

Compiler Error due to (b=a+2) in the first printf().

No compile error but output would be =11 X= where X would depend on compiler implementation.

What’s going to happen when we compile and run the following C program snippet? C #include <stdio.h> int main() { int a = 10; printf("=%d %d=",(a+1)); return 0; }

=11 X= where X would depend on Compiler implementation

Compiler Error due to missing argument for second %d

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Question 1

"Why is the & (address-of) operator used with scanf() when reading integer values?

Question 2

For a given integer, which of the following operators can be used to “set” and “reset” a particular bit respectively?

Question 3

What’s going to happen when we compile and run the following C program snippet?

#include "stdio.h"
int main()
{
 int a = 10;
 int b = 15;

 printf("=%d",(a+1),(b=a+2));
 printf(" %d=",b);

 return 0;
}

=11 15=
=11 12=
Compiler Error due to (b=a+2) in the first printf().
No compile error but output would be =11 X= where X would depend on compiler implementation.

Question 4

What’s going to happen when we compile and run the following C program snippet?

#include <stdio.h>
int main()
{
 int a = 10;

 printf("=%d %d=",(a+1));

 return 0;
}

Question 5

As per C language standard, which of the followings is/are not keyword(s)? Pick the best statement. auto make main sizeof elseif

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